CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Impulse

For the compe...

Question

For the compensated attenuator of figure, the impulse response under the condition $R_{1} C_{1} = R_{2} C_{2}$ is

A

\frac{R_{2}}{R_{1} + R_{2}} [1 - e^{\frac{1}{R_{1} C_{1}}}] u (t)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

$\frac{R_{2}}{R_{1} + R_{2}} δ (t)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

$\frac{R_{2}}{R_{1} + R_{2}} u (t)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

\frac{R_{2}}{R_{1} + R_{2}} e^{\frac{1}{R_{1} C_{1}}} u (t)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$\frac{R_{2}}{R_{1} + R_{2}} δ (t)$

$Z_{2} (s) = \frac{R_{2} \times \frac{1}{C_{2} s}}{R_{2} + \frac{1}{C_{2} s}} = \frac{R_{2}}{R_{2} C_{2} S + 1}$

$Z_{1} (s) = \frac{R_{1} \times \frac{1}{C_{1} s}}{R_{1} + \frac{1}{C_{1} s}} = \frac{R_{1}}{R_{1} C_{1} s + 1}$

$\frac{V_{2} (s)}{V_{1} (s)} = \frac{Z_{2} (s)}{Z_{1} (s) + Z_{2} (s)}$

$R_{1} C_{1} = R_{2} C_{2}$

$\frac{V_{2} (s)}{V_{1} (s)} = \frac{\frac{R_{2}}{R_{2} C_{2} s + 1}}{\frac{R 1}{R_{2} C_{2} s + 1} + \frac{R 2}{R_{2} C_{2} s + 1}} = \frac{R_{2}}{R_{1} + R_{2}}$

$V_{2} (s) = \frac{R_{2}}{R_{1} + R_{2}} V_{1} (s)$

For impulse response.

$V_{1} (s) = 1$

$v_{1} (t) = δ (t)$

$v_{2} (t) = \frac{R_{2}}{R_{1} + R_{2}} δ (t)$

Suggest Corrections

thumbs-up

1

Similar questions

Let $c_{1} & c_{2}$ be the centers and $r_{1} & r_{2}$ be the radius of two circles. Then

Cases Conditions

p. 1. $| r_{1} - r_{2} | < c_{1} c_{2} < r_{1} + r_{2}$

q. 2. $| r_{1} - r_{2} | = c_{1} c_{2}$

r. 3. $c_{1} c_{2} < | r_{1} + r_{2} |$

s.

4. $r_{1} + r_{2} < c_{1} r_{2}$

t. 5. $r_{1} + r_{2} = c_{1} r_{2}$

Q. For the system shown in below figure, what is the transfer function

\frac{V_{o} (s)}{V_{i} (s)}

R_{1} = R_{2} = C_{1} = C_{2} = 1 u n i t

Q. Three circles

C_{1}, C_{2}

C_{3}

r_{1}, r_{2}

r_{1} + r_{2}

respectively are such that

C_{1}

C_{2}

touch each other externally and

C_{3}

internally. Another circle with radius

r_{3}

touches all the three circles. If

r_{1} > r_{2} > r_{3}

r_{1}, r_{2}, r_{3}

are in A.P. then

{(\frac{r_{1}}{r_{2}})}^{3}

Q. In the figure shown below,

R_{1} = 1 Ω, R_{2} = 2 Ω, C_{1} = 4 μ F, C_{2} = 2 μ F

, the time constants (in

μ s

) for the circuits

I, I I

I I I

respectively are

Q. Three Circles with centres

C_{1}, C_{2}, C_{3}

r_{1}, r_{2}, r_{3}

r_{1} < r_{2} < r_{3}

are placed as shown in the figure.
Then,

r_{2} =

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Glycolysis

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon