For the de Broglie wavelength of 10-17 m- momentum of a particle will beA- 13-25 - 10-17B- 26-5 - 10-7C- 6-6 - 10-17D- 3-3125 - 10-7

The correct option is C {p =h/λ=(6.62×10^ 34/10^ 17)=6.6 ×10^ 17 ...

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The Uncertainty Principle

For the de Br...

Question

For the de Broglie wavelength of $10^{- 17}$ m , momentum of a particle will be

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10^{- 17} m

(G i v e n h = 6.625 \times 10^{- 34} m)

4.5 \times 10^{- 10} m

(Planck's constant, h = 6.6 \times 10^{- 34} k g m^{2} s^{- 1})

2.5 \times 10^{- 10} m

(h = 6.6 \times 10^{- 34} k g m^{2} s^{- 1})

2.25 \times 10^{- 10} m

(h = 6.6 \times 10^{- 34} k g m^{2} s^{- 1})

4.5 \times 10^{- 10} m

(Planck's constant, h = 6.6 \times 10^{- 34} k g m^{2} s^{- 1})

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