For the electrochemical cell $M | M^{+} | | X^{-} | X, E^{o} (M^{+} | M) = 0.44 V$ and $E^{o} (X | X^{-}) = 0.33 V$ . Which one of the following is true for this data?

M + X \to M^{+} + X^{-}

is a spontaneous reaction

No worries! We‘ve got your back. Try BYJU‘S free classes today!

M^{+} + X^{-} \to M + X

is a spontaneous reaction

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

E_{c e l l} = 0.77 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E_{c e l l} = - 0.77 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $M^{+} + X^{-} \to M + X$ is a spontaneous reaction
$E_{c e l l}^{o} = E_{X}^{o} - E_{M}^{o} = 0.33 - 0.44 = - 0.11 V$
$M^{+} + X^{-} \to M + X$ is a spontaneous reaction.

Suggest Corrections

Similar questions

For the electrochemical cell, M|M⁺| | X |X^-, Pt. E^o(M⁺/M) = 0.44 V and E^o(X/X^-) = 0.33 V. From this data one can deduce that

M | M^{+} | | X^{-} | X, E_{M^{+} / M}^{o} = 0.44 V

E_{X / X^{-}}^{o} = 0.33 V

M | M^{+} | | X | X^{-}

E_{M^{+} / M}^{0} = 0.44 V

E_{X / X^{-}}^{0} = 0.33 V

M | M^{+} ∥ X^{-} | X

E_{(M^{+} | M)}^{o} = 0.44 V

E_{(X | X^{-})}^{o} = 0.33 V

0.5 a m p

(M | M^{\oplus}) | | (X^{⊖} | X), E_{(M^{\oplus} | M)}^{⊖} = 0.44 V,

E_{(x | X^{⊖})}^{⊖} = - 0.33 V

Join BYJU'S Learning Program