Question

For the equation $3x^2+px+3=0,p>0$, if one of the roots is the square of the other, then p is equal to

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

$\alpha +{\alpha }^2=-\frac{p}{3}and\alpha .{\alpha }^2=\frac{3}{3}ie,{\alpha }^3=1\Rightarrow \alpha =1,\omega ,{\omega }^{2}If\alpha =1\Rightarrow p=-6If\alpha =\omega \Rightarrow p=3butp>0\therefore p\ne -6Hence,p=3$