Question

For the equation $3x^2$+ px + 3 =0, p > 0 is one of the root is square of the other, then p is equal to

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

$\alpha +{\alpha }^2=-\frac{P}{3}and\alpha .{\alpha }^2=1$

$So\alpha =1,\omega ,{\omega }^2.If\alpha =1,$ p < 0

$If\alpha =\omega or{\omega }^2,wehave\omega +{\omega }^2=-\frac{p}{3}\Rightarrow -1=\frac{-p}{3}\Rightarrow p=3$