Question

For the equation given below, find the slope and the y-intercept:

$x+3y+5=0$

• A. $\frac{1}{3}and\frac{5}{3}$
• B. $-\frac{1}{3}and-\frac{5}{3}$
• C. $-3and\frac{3}{5}$
• D. $3and-\frac{5}{3}$

Answer 1

Answer: (B)

$-\frac{1}{3}and-\frac{5}{3}$

The equation of any straight line can be written as $y=mx+c$,

where $m$ is its slope and $c$ is its y - intercept.
$x+3y+5=0$ can be written as $3y=-x-5$ or $y=\frac{-1}{3}x-\frac{5}{3}$
Comparing this equation with the standard form of the equation, we get:
$m=-\frac{1}{3},c=-\frac{5}{3}$
Hence, slope of $x+3y+5=0$ is $-\frac{1}{3}$ and y - intercept is $-\frac{5}{3}$