For the equation s=10t+4t2, what is the acceleration of the body? Assume that the body has a constant acceleration.
8 m/s2
6 m/s2
4 m/s2
2 m/s2
Given equation is s=10t+4t2
⇒s=10t+12×8t2
Comparing with the second equation of motion, s=ut+12at2, we get a=8 m/s2.
When a body moving with a speed of 20 m/s. stops in 20 seconds, what is the acceleration?