For the equilibrium
$C O + H_{2} O ⇌ C O_{2} + H_{2}$ .
The relation between $K_{p}$ and $K_{c}$ at $25^{o}$ C and at $100^{o}$ C are:

K_{p} = K_{c}, K_{p} = K_{c}

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K_{p} = K_{c} (R T)^{- 1}, K_{p} = K_{c}

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K_{p} = K_{c} (R T), K_{p} = K_{c} (R T)

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K_{p} = K_{c} (R T), K_{p} = K_{c}

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Solution

The correct option is A $K_{p} = K_{c}, K_{p} = K_{c}$
The given reaction is :-
$C O + H_{2} O ⇌ {C O}_{2} + H_{2}$
we have, $K_{P} = K_{C} {(R T)}^{△ n}$
Here, $△ n = 1 + 1 - 1 - 1 = 0$
$\Rightarrow K_{P} = K_{C}$ (at the temperature)

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For the equilibriumCO+H2O⇌CO2+H2.The relation between Kp and Kc at 25oC and at 100oC are:

The correct option is A Kp=Kc,Kp=KcThe given reaction is :- CO+H2O⇌CO2+H2we have, KP=KC(RT)△n Here, △n=1+1−1−1=0⇒KP=KC (at the temperature)

For the equilibrium
$C O + H_{2} O ⇌ C O_{2} + H_{2}$ .
The relation between $K_{p}$ and $K_{c}$ at $25^{o}$ C and at $100^{o}$ C are:

The correct option is A $K_{p} = K_{c}, K_{p} = K_{c}$
The given reaction is :-
$C O + H_{2} O ⇌ {C O}_{2} + H_{2}$
we have, $K_{P} = K_{C} {(R T)}^{△ n}$
Here, $△ n = 1 + 1 - 1 - 1 = 0$
$\Rightarrow K_{P} = K_{C}$ (at the temperature)