Question

For the equilibrium in a closed vessel $P{Cl}_5\left(g\right)\rightleftharpoons P{Cl}_3\left(g\right)+{Cl}_2\left(g\right)$
$K_p$ is found to be double of $K_c$. This is attained when:

• A. $T=2K$
• B. $T=12.18K$
• C. $T=24.36K$
• D. $T=27.3K$

Answer 1

Answer: (A)

$T=2K$

$PC{l}_5\leftrightharpoons PC{l}_3+C{l}_2$

$K_p=\frac{\left[PC{l}_3\right]\left[C{l}_2\right]}{\left[PC{l}_5\right]}{\left(RT\right)}^{△n}$

$K_p=K_c{\left(RT\right)}^{△n}$

According to the question

$K_p=2K_c$

Therefore,

$2K_c=K_c{\left(RT\right)}^{(2-1)}$

$2=RT$

$T=2K$ (R is the universal gas constant)