For the first order decomposition reaction of N 2 O 5- it is observed that i N - 2 O - 5 g -rightarrow 2 NO - 2 g -lfrac12 O - 2 g - frac- d - N - 2 O - 5- dt - k - N - 2 O - 5- 1ii 2 N - 2 O - 5 g rightarrow 4 NO - 2 g - O - 2 g - frac- d - N - 2 O - 5- dt - k - N - 2 O - 5-Which of the following is true- A- k -2 k -B- k - k -2C- k - k -1-2D- k - k -

The correct option is C k=k'^1/2Take ratio of both equations ...

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Question

For the first order decomposition reaction of $N_{2} O_{5}$ , it is observed that
$(i) N_{2} O_{5} (g) \to 2 N O_{2} (g) + \frac{1}{2} O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}] (i i) 2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k^{'} [N_{2} O_{5}]$
Which of the following is true?

k = k^{'}

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k = 2 k^{'}

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k = \frac{k^{'}}{2}

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k = k^{' \frac{1}{2}}

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N_{2} O_{5}

(i) N_{2} O_{5} (g) \to 2 N O_{2} (g) + \frac{1}{2} O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}] (i i) 2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k^{'} [N_{2} O_{5}]

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2} \frac{- d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}], \frac{d [N O_{2}]}{d t} = K_{2} [N_{2} O_{5}], a n d \frac{d [O_{2}]}{d t} = K_{3} [N_{2} O_{5}]

K_{1}, K_{2}

K_{3}

2 N_{2} O_{5} \to 4 N O_{2} + O_{2}

\frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k^{^{'}} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k^{''} [N_{2} O_{5}]

k

k^{^{'}}

k

k^{''}

N_{2} O_{5}

(i) N_{2} O_{5} (g) \to 2 N O_{2} (g) + \frac{1}{2} O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k [N_{2} O_{5}] (i i) 2 N_{2} O_{5} (g) \to 4 N O_{2} (g) + O_{2} (g); \frac{- d [N_{2} O_{5}]}{d t} = k^{'} [N_{2} O_{5}]

N_{2} O_{5} ⟶ 2 N O_{2} + \frac{1}{2} O_{2}

\frac{- d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

k_{1}, k_{2}

k_{3}

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