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Byju's Answer

Standard XII

Chemistry

Faraday's First Law

For the follo...

Question

For the following cell, $Z n (s) | Z n S O_{4} (a q) ∥ C u S O_{4} (a q) | C u (s)$ , when the concentration of $Z n^{2 +}$ is $10$ times the concentration of $C u^{2 +}$ , the expression for $△ G$ (in $J m o l^{- 1}$ ) is:
[ $F$ is Faraday constant; $R$ is gas constant; $T$ is temperature; $E^{\circ} (c e l l) = 1.1 V]$

2.303 R T - 2.2 F

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2.303 R T + 1.1 F

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1.1 F

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- 2.2 F

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Solution

The correct option is A $2.303 R T - 2.2 F$
$Z n + C u^{2 +} \to Z n^{2 +} + C u$

$E_{c e l l}^{0} = 1.1 V$ (given)

$E_{c e l l} = E_{c e l l}^{0} - \frac{2.303 R T}{n F} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$
$E_{c e l l} = 1.1 V - \frac{2.303 R T}{n F} l o g \frac{10 [C u^{2 +}]}{[C u^{2 +}]}$
$E_{c e l l} = 1.1 V - \frac{2.303 R T}{2 F}$

Now,

$Δ G = - n F E_{c e l l}$

$Δ G = - 2 F \times [1.1 V - \frac{2.303 R T}{2 F}]$

$Δ G = 2.303 R T - 2.2 F$

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Similar questions

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When the concentration of

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Δ G (i n J m o l^{- 1})

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Q. For the following cell,

Z n (s) | {Z n S O}_{4} (a q) ∥ {C u S O}_{4} (a q) | C u (s)

When the concentration of

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For the following cell, Zn(s)|ZnSO4(aq)∥CuSO4(aq)|Cu(s), when the concentration of Zn2+ is 10 times the concentration of Cu2+, the expression for △G (in J mol−1) is:[F is Faraday constant; R is gas constant; T is temperature; E∘(cell)=1.1 V]

The correct option is A 2.303RT−2.2FZn+Cu2+→Zn2++CuE0cell=1.1V (given)Ecell=E0cell−2.303RTnFlog[Zn2+][Cu2+]Ecell=1.1V−2.303RTnFlog10[Cu2+][Cu2+]Ecell=1.1V−2.303RT2FNow,ΔG=−nFEcellΔG=−2F×[1.1V−2.303RT2F]ΔG=2.303RT−2.2F