Question

For the following circuit, identify the equivalent gate.

• A. $Y=A+B$
• B. $Y=A\cdot B$
• C. $Y=\overline{A}+B$
• D. $Y=A+\overline{B}$

Answer 1

The correct option is A $Y=A+B$

A	B	$\overline{A}$	$\overline{B}$	$Y=\overline{(\overline{A}.\overline{B})}=A+B$
0	0	1	1	0
0	1	1	0	1
1	0	0	1	1
1	1	0	0	1

Therefore, for the given logic gate circuit, the equivalent output is that of an OR gate, i.e. $Y=A+B$

Hence, $\left(C\right)$ is the correct answer.