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Mixed Combination of Cells

For the follo...

Question

For the following circuits, the potential difference between X and Y in volt is:

\frac{2}{3}

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\frac{4}{3}

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\frac{8}{9}

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\frac{5}{3}

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Solution

The correct option is A $\frac{2}{3}$
$T h e g i v e n c i r c u i t c a n b e s h o w n a s i n t h e f i g u r e N o w e q u i v a l e n t r e s i s t a n c e b e c o m e s 6 Ω / 2 = 3 Ω n o w t h e c u r r e n t i n t h e c i r c u i t = 2 / 3 A A n d c u r r e n t i n o n e o f t h e p a r a l l e l b r a n c h = 1 / 3 A p o t e n t i a l o f t h e p o i n t x = 2 - 1 / 3 \times 2 = \frac{4}{3} V P o t e n t i a l o f t h e p o i n t y = 2 - 1 / 3 \times 4 = \frac{2}{3} V S o t h e d i f f e r e n c e i n t h e v o l t a g e o f p o i n t s x a n d y b e c o m e s = \frac{2}{3} V$

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\frac{9 x}{8}

\frac{y}{7}

\frac{y - 4}{3}

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\frac{x - 9}{x - 5}

\frac{5}{7}

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\frac{b + (b + 1) + (b + 2)}{4}

X

Y

\frac{x - 2}{2} = \frac{y - 1}{5} = \frac{z + 3}{- 3}

\frac{x + 2}{- 1} = \frac{y - 4}{8} = \frac{z - 5}{4}

\frac{x}{2} = \frac{y}{2} = \frac{z}{1}

\frac{x - 5}{4} = \frac{y - 2}{1} = \frac{z - 3}{8}

Find the angle between the following pairs of lines:

(i)

(ii)

Find the angle between the following pair of lines

$\frac{x - 2}{2} = \frac{y - 1}{5} = \frac{z + 3}{- 3} a n d \frac{x + 2}{- 1} = \frac{y - 4}{8} = \frac{z - 5}{4}$

$\frac{x}{2} = \frac{y}{2} = \frac{z}{1} a n d \frac{z - 5}{4} = \frac{y - 2}{1} = \frac{z - 3}{8}$

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