Question

For the following diagram calculate final pressure (in atm) when both valves are opened. Given that temperature $\left(T\right)$ is the same for each container.

Answer 1

Final pressure can obtained by :

$P=\frac{(n_{He}+n_{Ne}+n_{Xe})RT}{V_{He}+V_{Ne}+V_{Xe}}$

$\Rightarrow P=\frac{P_{He}{V}_{He}+P_{Ne}{V}_{Ne}+P_{Xe}.V_{He}}{V_{He}+V_{Ne}+V_{Xe}}$

$=\frac{1.5\times 2+2.5\times 4+1\times 1}{2+4+1}$

$=2$ atm