For the following reaction: PCl5(g)⇌PCl3(g)+Cl2(g) 0.4mol of PCl5(g), 0.2mol of PCl3(g) and 0.6mol of Cl2(g) are taken in a 1L flask.
If Kc=0.2, then the direction in which reaction proceeds is :
A
Towards reactant side
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B
Towards products side
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C
Reaction is at equilibrium
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D
None of the above
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Solution
The correct option is A Towards reactant side Given Reaction is: PCl5(g)⇌PCl3(g)+Cl2(g) Concentration=MolesVolume [PCl5]=0.41=0.4M[PCl3]=0.21=0.2M[Cl2]=0.61=0.6M
Finding Qc Qc=[PCl3][Cl2][PCl5]
puttting the values, Qc=0.2×0.60.4=0.3M>Kc(=0.2)
Since, Q>Kc the reaction proceeds in backward direction i.e. reactant (PCl5) side.