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Characteristics of Equilibrium Constant

For the follo...

Question

For the following reaction, the equilibrium constant $K_{c}$
at 298 K is $1.6 \times 10^{17}$
$F e^{2 +} (a q) + S^{2 -} (a q) ⇌ F e S (s)$
When equal volumes of $0.06 M F e^{2 +} (a q) a n d 0.2 M S^{2 -} (a q)$
solutions are mixed, the equilibrium
concentration of $F e^{2 +} (a q)$ is found to be $Y \times 10^{- 17} M .$ The value of Y is

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Solution

$F e^{2 +} (a q) + S^{2 -} (a q) ⇌ F e S (s) (K_{c} = 1.6 \times 10^{17}$
Initial $0.06 M 0.2 M$
After mixing $0.03 M 0.1 M$
$? 0.07 M$
$1.6 \times 10^{17} = \frac{1}{[F e^{2 +}] \times 0.07} o r [F e^{2 +}] = \frac{10^{- 17}}{1.6 \times 0.07} = \frac{10^{- 15}}{11.2} = 8.928 \times 10^{- 17} o r 8.93 \times 10^{- 17} = Y \times 10^{- 17}$
or $8.93 \times 10^{- 17} = Y \times 10^{- 17}$

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Similar questions

K_{c}

1.6 \times 10^{17}

F e^{2 +} (a q) + S^{2 -} (a q) ⇌ F e S (s)

0.06 M F e^{2 +} (a q) a n d 0.2 M S^{2 -} (a q)

F e^{2 +} (a q)

Y \times 10^{- 17} M .

K_{c}

1.6 \times 10^{17}

F e^{2 +} (a q) + S^{2 -} (a q) ⇌ F e S (s)

0.06 M F e^{2 +} (a q) a n d 0.2 M S^{2 -} (a q)

F e^{2 +} (a q)

Y \times 10^{- 17} M .

E_{c e l l} = 0.2905 V

Z n (s) + F e^{2 +} (a q) 0.01 M \to Z n^{2 +} 0.1 M (a q) + F e (s)

Z n^{2 +} (a q .) + 2 e ⇌ Z n (s); - 0.762

C r^{3 +} (a q) + 3 e ⇌ C r (s); - 0.740

2 H^{+} (a q) + 2 e ⇌ H_{2} (g); 0.00

F e^{3 +} (a q) + e ⇌ F e^{2 +} (a q); 0.770

2 {F e}^{3 +} (a q) + {({H g}_{2})}^{2 +} (a q) ⇌ 2 {F e}^{2 +} (a q) + 2 {H g}^{2 +} (a q)

K_{c} = 9.14 \times 10^{- 6}

25

[{F e}^{3 +}] = 0.5 M, [{H g}_{2}^{2 +}] = 0.5 M, [{F e}^{2 +}] = 0.03 M

[{H g}^{2 +}] = 0.03 M

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