Question

For the following system of equations determine the value of $k$ for which they have a unique solution.
$2x+3y=5$
$kx-6y=8$

Answer 1

$2x+3y=5$

$kx-6y=8$

for unique solution,

$\frac{a_1}{a_2}\ne$$\frac{b_1}{b_2}$

$\frac{2}{k}\ne \frac{3}{-6}$

$\frac{2}{k}\ne \frac{1}{-2}$

$k\ne -4$

So , value of k ≠ -4