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Introduction to Le Chatelier's Principle

For the follo...

Question

For the following three reactions a, b, and c, equilibrium constants are given:
(A) $C O (g) + H_{2} O (g) ⇋ C O_{2} (g) + H_{2} (g); K_{1}$
(B) $C H_{4} (g) + H_{2} O (g) ⇋ C O (g) + 3 H_{2} (g); K_{2}$
(C) $C H_{4} (g) + 2 H_{2} O (g) ⇋ C O_{2} (g) + 4 H_{2} (g); K_{3}$
Which of the following relations is correct

K_{2} K_{3} = K_{1}

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K_{3} = K_{1} K_{2}

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K_{3} K_{2}^{3} = K_{1}^{2}

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K_{1} \sqrt{K_{2}} = K_{3}

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Solution

The correct option is B $K_{3} = K_{1} K_{2}$
For the following reactions:
$(A) C O_{(g)} + H_{2} O_{(g)} ⇋ C O_{2 (g)} + H_{2 (g)}; K_{1} (B) C H_{4 (g)} + H_{2} O_{(g)} + ⇋ C O_{(g)} + 3 H_{2}; K_{2}$
On adding both equation we get equation C.
$C H_{4 (g)} + 2 H_{2} O_{(g)} ⇋ C O_{2 (g)} + 4 H_{2}; K_{3}$
Thus, the equilibrium constant are related as
So, $K_{3} = K_{1} . K_{3}$

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Similar questions

C O (g)

+ H_{2} O (g) ⇋ C O_{2} (g) + H_{2} (g); K_{1}

C H_{4} (g) + H_{2} O (g) ⇋ C O (g) + 3 H_{2} (g); K_{2}

C H_{4} (g) + 2 H_{2} O (g) ⇋ C O_{2} (g) + 4 H_{2} (g); K_{3}

C O

(g) + H_{2} O (g) ⇌ C O_{2} (g) + H_{2} (g)

K_{1}

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C H_{4} (g) + 2 H_{2} O (g) ⇌ C O_{2} (g) + 4 H_{2} (g); K_{3}

C O (g) + H_{2} O (g) ⇌ {C O}_{2} (g) + H_{2} (g); K_{1}

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{C H}_{4} (g) + 2 H_{2} O (g) ⇌ {C O}_{2} (g) + {4 H}_{2} (g); K_{3}

(i) C O (g) + H_{2} O (g) ⇌ C O_{2} (g) + H_{2} (g); K_{1} (i i) C H_{4} (g) + H_{2} O (g) ⇌ C O (g) + 3 H_{2} (g); K_{2} (i i i) C H_{4} (g) + 2 H_{2} O (g) ⇌ C O_{2} (g) + 4 H_{2} (g); K_{3}

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C H_{4} (g) + 2 H_{2} O (g) ⇌ C O (g) + 4 H_{2} (g); K_{2}

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