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Question

For the following three reactions a, b, c, equilibrium constants are given:

1. CO (g)+H2O(g)CO2(g)+H2(g) ; K1
2. CH4(g)+H2O(g)CO(g)+3H2(g);K2
3. CH4(g)+2H2O(g)CO2(g)+4H2(g);K3
Which of the following relations is correct?

A
K3=K1K2
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B
K3K32=K21
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C
K1K2=K3
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D
K2K3=K1
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Solution

The correct option is A K3=K1K2
CO(g)+H2O(g)CO2(g)+H2(g) ; K1
CH4(g)+H2O(g)CO(g)+3H2(g);K2
Adding both equations, we get

CH4(g)+2H2O(g)CO2(g)+4H2(g);K3=K1×K2

So, K3=K1K2

Hence, option A is correct

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