For the given cell reaction: $F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}$ . The equilibrium constant is:
(Given: $E_{{C e}^{4 +} / C e^{3 +}}^{\circ} = 1.44 V; E_{F e^{2 +} / F e^{3 +}}^{\circ} = 0.68 V$ )

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Solution

$F e^{2 +} + C e^{4 +} \leftrightarrow F e^{3 +} + C e^{3 +}$
$E_{c e l l}^{o} = E_{O P_{F e^{2 +} / F e^{3 +}}}^{o} + E_{R P_{C e^{4 +} / C e^{3 +}}}^{o}$
$= - 0.68 + 1.44$
$= 0.76 V$
$E_{c e l l}^{o} = \frac{0.059}{1} {log}_{10} K_{C}$
$∴ {log}_{10} K_{C} = \frac{0.76}{0.059} = 12.8814$
or $K_{C} = 7.6 \times 10^{12}$ .

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Similar questions

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} | C e^{3 +}}^{o} = 1.44 V; E_{F e^{3 +} | F e^{2 +}}^{o} = 0.68 V

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{0} = 1.44 V; E_{F e^{3 +} / F e^{2 +}}^{0} = 0.68 V]

F e^{2 +} + C e^{4 +} ⇌ F e^{3 +} + C e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{o} = 1.44 V; E_{F e^{3 +} / F e^{2 +}}^{o} = 0.68 V

F e^{2 +} + C e^{4 +} | F e^{3 +} + C e^{3 +}

E^{0} C e^{4 +} / C e^{3 +} = 1.44

E^{0} F e^{3 +} / F e^{2 +} = 0.68 V]

F e^{2 +} + C e^{4 +} ⇌ C e^{3 +} + F e^{3 +}

E_{C e^{4 +} / C e^{3 +}}^{\circ} = 1.44 V

E_{F e^{3 +} / F e^{2 +}}^{\circ} = 0.68 V

\frac{2.303 R T}{F} = 0.06

25^{o} C, l o g 4.68 = 0.67

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