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Question

# For the given circuit, which of the mentioned below input will give output as 1.

A
P = 0 ; Q = 0
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B
P = 1 ; Q = 0
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C
P = 0 ; Q = 1
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D
Either P = 1 or Q = 1
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Solution

## The correct option is C P = 0 ; Q = 1S=[¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(P+Q)+¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(P+(P+Q))]¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(P+(P+Q)) Considering, ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯P+Q=Xand¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯P+(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯P+Q)=Y Then, S=(X+Y)Y=XY+Y=Y S=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯P+(¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯P+Q)=¯¯¯¯P.(P+Q)=¯¯¯¯PQ So far, S = 1, P = 0, Q = 1

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