For the given experimental setup, the oscillation frequency of the mass is f.S1 and S2 are identical springs. One spring is now removed, then frequency will become.
A
2f
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B
f√2
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C
f√3
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D
√2f
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Solution
The correct option is Bf√2 Frequency f=12π√keqm =12π√2km One spring is removed, then keq=k f′=12π√km ⇒ff′=√2 ⇒f′=f√2