For the given isosceles triangle ABC such that AB=AC and AD bisects the line BC, such that AC≠DC then ∠DAC=
A
∠DAB
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B
∠ADC
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C
∠C
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Solution
The correct option is A∠DAB
For the isosceles triangle ABC,AD bisects BC ⇒ΔADB≅ΔADC
(By S - S - S congruency) ∴ The corresponding angles will be equal. ⇒∠DAC=∠DAB
Also, AC≠DC⇒∠DAC≠∠C