For the given linear equation y - 3x - 1 - 0- what are the values of y if nbsp-x - -3- -4- 2- nbsp- 5- -8- 13-8- 5- 13-8- 8- 8-8- -13- 5-

The correct option is D 8, 13, 5 We have y 3x+1= 0 For x = 3 ⇒ y 3(3) + 1 = 0 ∴ y = 8 For x = 4 ⇒ y 3( 4) +1 = 0 ∴ y = 13 For x = 2 ⇒ y 3(2) + 1 = ...

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Byju's Answer

Standard VIII

Mathematics

Linear equation

For the given...

Question

For the given linear equation $y - 3 x + 1 = 0,$ what are the values of $y$ if $x = [3, - 4, 2]$ ?

5, -8, 13

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8, 5, 13

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8, 8, 8

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8, -13, 5

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Solution

The correct option is D
8, -13, 5

We have $y - 3 x + 1 = 0$

For $x = 3$
$\Rightarrow y - 3 (3) + 1 = 0$
$∴ y = 8$

For $x = - 4$
$\Rightarrow y - 3 (- 4) + 1 = 0$
$∴ y = - 13$

For $x = 2$
$\Rightarrow y - 3 (2) + 1 = 0$
$∴ y = 5$

Thus, the values of $y$ if $x = [3, - 4, 2]$ are 8, -13 and 5 respectively.

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For the given linear equation y−3x+1=0, what are the values of y if x=[3,−4,2]?

The correct option is D 8, -13, 5 We have y−3x+1=0 For x=3 ⇒y−3(3)+1=0 ∴y=8 For x=−4 ⇒y−3(−4)+1=0 ∴y=−13 For x=2 ⇒y−3(2)+1=0 ∴y=5 Thus, the values of y if x=[3,−4,2] are 8, -13 and 5 respectively.

For the given linear equation $y - 3 x + 1 = 0,$ what are the values of $y$ if $x = [3, - 4, 2]$ ?