Question

For the given linear equation $y-3x+1=0,$ what are the values of $y$ if $x=[3,-4,2]$?

• A. 8, 5, 13
• B. 8, 8, 8
• C. 8, -13, 5
• D. 5, -8, 13

Answer 1

The correct option is C

8, -13, 5

We have $y-3x+1=0$

For $x=3$
$\Rightarrow y-3\left(3\right)+1=0$
$\therefore y=8$

For $x=-4$
$\Rightarrow y-3(-4)+1=0$
$\therefore y=-13$

For $x=2$
$\Rightarrow y-3\left(2\right)+1=0$
$\therefore y=5$

Thus, the values of $y$ if $x=[3,-4,2]$ are 8, -13 and 5 respectively.