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Question

For the given reaction :

S8 (s)+12NaOH (aq)4Na2S (aq)+2Na2S2O3 (aq)+6H2O (l)
What will be the overall valence factor (nf) for S8?

A
16
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B
8
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C
5
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D
20
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Solution

The correct option is B 8
This is a disproportionation reaction where Sulphur simulataneously gets oxidised and reduced.

Reaction :
0S8 (s)+12NaOH (aq)4Na22S (aq)+2Na2+2S2O3 (aq)+6H2O (l)

Oxidation :
0S8 (s)2Na2+2S2O3
(nf)oxidation=|0(+2)|×8(nf)oxidation=16

Reduction:
0S8 (s)4Na22S (aq)
(nf)reduction=|0(2)|×8(nf)reduction=16

(nf)overall=(nf)oxidation×(nf)reduction(nf)oxidation+(nf)reduction

(nf)overall=16×1616+16=25632(nf)overall=8

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