For the polynomial $p (x) = 2 x^{2} + 3 x^{n + 1} + 6$ , the sum of all the exponents of the variable terms is 6. What is the value of n?

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Solution

The correct option is D 3
The variable exponents of the polynomial $p (x) = 2 x^{2} + 3 x^{n + 1} + 6$ are 2 and $n + 1$

Given, sum of exponents = 6
$\Rightarrow n + 1 + 2 = 6$
$\Rightarrow n + 3 = 6$
$\Rightarrow n = 3$

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