Question

For the reaction $2A\left(g\right)\rightleftharpoons B\left(g\right)+3C\left(g\right),$ at a given temperature, $K_c=16mo{l}^2{L}^{-2}$. What must be the volume (in L) of the flask, if a mixture of $2$ mole each of A, B and C exist in equilibrium?

• A. $\frac{1}{4}$
• B. $\frac{1}{2}$
• C. $1$
• D. None of these

Answer 1

The correct option is B $\frac{1}{2}$

$2A\rightleftharpoons B+3C{K}_c=\frac{\left[B\right][C{]}^3}{[A{]}^2}16=\frac{\left(\frac{2}{V}\right){\left(\frac{2}{V}\right)}^3}{{\left(\frac{2}{V}\right)}^2}16={\left(\frac{2}{V}\right)}^{2}4=\frac{2}{V}V=\frac{1}{2}L$