Question

For the reaction, $2HgO\left(s\right)\to 2Hg\left(l\right)+O_2\left(g\right)$:

• A. $\Delta H>0$ and $\Delta S<0$
• B. $\Delta H>0$ and $\Delta S>0$
• C. $\Delta H<0$ and $\Delta S<0$
• D. $\Delta H<0$ and $\Delta S>0$

Answer 1

Answer: (B)

$\Delta H>0$ and $\Delta S>0$

The above given equation is decomposition reaction in a compound is breaking into its elements so energy is required to break down into its elements.

So $\Delta H>0$
Since solid is getting converted into liquid and gas its randomness is increasing.

So, $\Delta S>0$.