For the reaction - 2NO2g- 2NOg-O2g- Kc-1-8- 10-6 at 184oC R- 0-082 L atm-mol- KWhen Kp and Kc are compared at 184oC- it is found that

The correct option is D K_p is greater than K_c For the reaction : #160; 2NO_2(g)⇌ 2NO(g)+O_2(g) Given: K_c=1.8× 10^ 6 at 184^oC ...

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Byju's Answer

Standard XII

Chemistry

Derivation of Kp and Kc

For the react...

Question

For the reaction :
$2 N O_{2 (g)} ⇌ 2 N O_{(g)} + O_{2 (g)}, (K_{c} = 1.8 \times 10^{- 6}$ at $184^{o} C) (R = 0.082 L a t m / (m o l . K)$

When $K_{p}$ and $K_{c}$ are compared at $184^{o} C$ , it is found that

Whether

K_{p}

is greater than, less than or equal to

K_{c}

depends upon the total gas pressure

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K_{p} = K_{c}

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K_{p}

is less than

K_{c}

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K_{p}

is greater than

K_{c}

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Solution

The correct option is D $K_{p}$ is greater than $K_{c}$
For the reaction :
$2 N O_{2} (g) ⇌ 2 N O (g) + O_{2} (g)$

Given:
$K_{c} = 1.8 \times 10^{- 6}$ at $184^{o} C$

$Δ n = 3 - 2 = 1$

$R = 0.082 L a t m / m o l . K$

$T = 184^{0} C = 184 + 273 = 457 K$

$K_{p} = K_{c} (R T)^{Δ n}$

$K_{p} = 1.8 \times 10^{- 6} \times 0.082 \times 457 = 6.836 \times 10^{- 5}$
Hence it is clear that $K_{p} > K_{c}$

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Similar questions

Q. For the reaction,

2 N O_{2} (g) ⇌ 2 N O (g) + O_{2} (g)

.
(

K_{c} = 1.8 \times 10^{- 6}

184^{o} C

(R = 0.0831 k J / (m o l . K J))

when

K_{p}

and

K_{c}

are compared at

184^{o} C

it is found that
(1) Whether

K_{p}

is greater then, less then or equal to

K_{c}

depends upon the total gas pressure
(2)

K_{p} = K_{c}

(3)

K_{p}

is less then

K_{c}

(4)

K_{p}

is greater then

K_{c}

Q. For the reaction,

2 N O_{2} (g) ⇋ 2 N O (g) + O_{2} (g), (K_{C} = 1.8 \times 10^{- 6} a t 184^{\circ} C)

(R = 0.0831 kJ/(mol.K))
when

K_{p}

and

K_{c}

are compared at

184^{\circ} C

it is found that

Q. For the reaction

2 {N O}_{2} (g) ⇌ 2 N O (g) + O_{2} (g)

K_{c} = 1.8 \times 10^{- 6}

184^{o} C

R = 0.0831 k J K^{- 1} {m o l}^{- 1}

when

K_{p}

and

K_{c}

are compared at

184^{o} C

it is found that:

Q. For the reaction given,

2 N O_{2} (g) ⇋ 2 N O (g) + O_{2} (g)

K_{c} = 1.8 \times 10^{- 6}

184^{\circ} C

and

R = 0.08311

kJ/mol.K. When

K_{p}

and

K_{c}

are compared at

184^{\circ} C

, it is found that:

Q. Assertion :

K_{p}

can be equal to or less than or even greater than the value of

K_{c}

. Reason:

K_{p} = K_{c} {(R T)}^{Δ n}

the relation between

K_{p}

and

K_{c}

depends on the change in the number of moles of gaseous reactants and products.

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For the reaction : 2NO2(g)⇌2NO(g)+O2(g),(Kc=1.8×10−6 at 184oC)(R=0.082Latm/(mol.K)When Kp and Kc are compared at 184oC, it is found that

The correct option is D Kp is greater than KcFor the reaction : 2NO2(g)⇌2NO(g)+O2(g)Given:Kc=1.8×10−6 at 184oCΔn=3−2=1R=0.082Latm/mol.KT=1840C=184+273=457KKp=Kc(RT)ΔnKp=1.8×10−6×0.082×457=6.836×10−5Hence it is clear that Kp>Kc

For the reaction :
$2 N O_{2 (g)} ⇌ 2 N O_{(g)} + O_{2 (g)}, (K_{c} = 1.8 \times 10^{- 6}$ at $184^{o} C) (R = 0.082 L a t m / (m o l . K)$

When $K_{p}$ and $K_{c}$ are compared at $184^{o} C$ , it is found that