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Derivation of Kp and Kc

For the react...

Question

For the reaction: $2 N O_{2} (g) ⇌ 2 N O (g) + O_{2} (g)$ : $K_{c} = 1.8 \times 10^{- 6}$ at $184^{o}$ C and $R = 0.083$ $J K^{- 1}$ $m o l^{- 1}$ . When $K_{p}$ and $K_{c}$ are compared at $184^{o}$ C, it is found that:

A

K_{p} > K_{c}

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B

K_{p} < K_{c}

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C

K_{p} = K_{c}

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D

K_{p} < > K_{c}

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Solution

The correct option is C $K_{p} > K_{c}$
$K_{p} = K_{c} (R T)^{Δ n}$
$Δ n = 3 - 2 = 1$
$K_{p} = K_{c} (0.0831 \times 457)^{1}$
$K_{p} > K_{c}$

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Similar questions

Q. For the reaction ;

2 N O_{2} (g) ⇌ 2 N O (g) + O_{2} (g)

K_{c} = 1.8 \times 10^{- 6}

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J K^{- 1} m o l^{- 1}

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Q. For the reaction

2 {N O}_{2} (g) ⇌ 2 N O (g) + O_{2} (g)

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R = 0.0831 k J K^{- 1} {m o l}^{- 1}

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K_{c} = 1.8 \times 10^{- 6}

^{o}

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2 N O_{2} (g) ⇌ 2 N O (g) + O_{2} (g)

K_{c} = 1.8 \times 10^{- 6}

184^{o} C

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K_{p}

K_{c}

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it is found that
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K_{p}

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K_{p}

K_{c}

K_{p}

is greater then

K_{c}

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