For the reaction: 2NOCl(g)⇌2NO(g)+Cl2(g), Kc at 427oC is 3×106M. The value of Kp is nearly:
A
7.5×10−5
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B
2.5×10−5
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C
2.5×10−4
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D
1.75×10−4
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Solution
The correct option is D1.75×10−4 For the reaction: 2NOCl(g)⇌2NO(g)+Cl2(g), Kc at 427oC is 3×10−6M. The value of Kp is nearly 1.75×10−4. Δn=(2+1)−2=1 Kp=Kc(RT)Δn Kp=Kc(RT)1 Kp=Kc(RT) Kp=3×10−6M×0.08206Latm/mol/K×(427+273)K Kp=1.75×10−4atm