Question

For the reaction $2O_3\left(g\right)\to 3O_2\left(g\right),△H$ is negative, $△S$ and $△G$ are respectively:

• A. +ve, +ve
• B. +ve, -ve
• C. -ve, +ve
• D. -ve, - ve

Answer 1

The correct option is B +ve, -ve

$2O_3\left(g\right)\to 3O_2\left(g\right);△H=-ve\left(given\right);now,△S=+ve$
as the moles of gas are increasing.

We also know,
and $△G$= $△H$ - $T△S$
from the given values
$△G$ =$-ve$ - $(+ve)$
=$-ve$
So, $△G$ will be negative for this.