For the reaction

$3 {B r}_{2}$ + $6 {O H}^{Θ}$ $\to$ $5 {B r}^{Θ}$ + $B r {O_{3}}^{Θ}$ + $3 H_{2} O$

Equivalent weight of ${B r}_{2}$ (Molecular weight M) is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C

${B r}_{2}$ + $2 e^{Θ}$ $\to$ ${B r}_{2}$ (reduction)

${B r}_{2}$ $\to$ $B r {O_{3}}^{Θ}$ + $10 e^{-} s$ (oxidation)

Eq.wt = $\frac{M}{2}$ + $\frac{M}{10}$

Suggest Corrections

Similar questions

For the reaction 3 $B r_{2} + 6 O H^{-} \to 5 B r^{-} + B r O_{3}^{-} + 3 H_{2} O$
Equivalent weight of $B r_{2}$ is [M = mol wt of $B r_{2}$ ]

5 B r^{-} + B r O_{3}^{-} + 6 H^{+} \to 3 B r_{2} + 3 H_{2} O

B r_{2}

M

3 B r_{2} + 6 O H^{⊖} \to 5 B r^{⊖} + B r O_{3}^{⊖} + 3 H_{2} O

B r_{2}

M

B r_{2}

3 B r_{2} + 6 O H^{-} \to 5 B r^{-} + B r O_{3}^{-} + 3 H_{2} O

B r_{2}

B r^{-}

{B r O_{3}}^{-}

3 B r_{2} + 6 O H^{-} \to 5 B r^{-} + {B r O_{3}}^{-} + 3 H_{2} O

B r_{2}

= M

Join BYJU'S Learning Program