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Question

For the reaction
5Br(aq)+6H+(aq)+BrO3(aq)3Br2(aq)+3H2O(l)
if, [BrO3]t=0.01 mol L1min1,
[Br2]t in mol L1min1 is:

A
0.01
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B
0.3
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C
0.03
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D
0.005
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Solution

The correct option is C 0.03
Rate of reaction= DecreaseintheconcentrationofreactantTimeinterval
or, =IncreaseintheconcentrationofProductsTimeinterval
Rate of reaction=Δ[R]Δt=+Δ[P]Δt
As, Δ[BrO3]Δt=0.01mol/L/min
Then for, Δ[Br2]Δt=+13Δ[Br2]Δt=Δ[BrO3]Δt
13×Δ[Br2]Δt=0.01
So, Δ[Br2]Δt=0.01×3=0.03molL1min1

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