wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For the reaction, Ag+(aq)+Cl(aq)AgCl(s)
Given:
SpeciesΔGf(kJ/mol)Ag+(aq)+77Cl(aq)129AgCl(s)109
Calculate Ecell at 298 K.
Also find the solubility product of AgCl.

A
0.59 V and Ksp=1010
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.79 V and Ksp=3×105
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.36 V and Ksp=1014
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.59 V and Ksp=1010
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.59 V and Ksp=1010

Ag+1(aq) + Cl1 AgCl(s)

ΔGorxn = ΔGof(products)ΔGof(reactants)

=109+12977

=55 kJmol1

Ag(s) Ag+ + e(aq) ----1

12Cl2(1atm) +e Cl(aq) ----2

Adding 1 and 2

Ag(s) + 12Cl2(g) Ag+(aq) + Cl(aq)

n=1

ΔGorxn = 55

For the reverse reaction,

ΔGorxn = 55

nFΔEorxn = 55

1× 96500 × ΔEo = 55

ΔEo = 0.59

ΔEo = 0.0591 log(KspAgCl)

0.59 = 0.059 log(KspAgCl)

log(KspAgCl) = 10

KspAgCl = 1010


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Operator "Of"
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon