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Balancing Redox Equations

For the react...

Question

For the reaction between $K M n O_{4}$ and $H_{2} O_{2}$ , the number of electrons transferred per mole of $H_{2} O_{2}$ is:

One

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Two

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Three

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Four

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Solution

The correct option is B Two
The half reactions are:
$2 M n O_{4}^{-} + 16 H^{+} + 10 e^{-} \to 2 M n^{2 +} + 8 H_{2}$
$5 H_{2} O_{2} \to 5 O_{2} + 10 H^{+} + 10 e^{-}$
The number of electron transferred per mole of hydrogen peroxide $= 10 / 5 = 2$ .
Hence, option (b) is the correct answer.

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