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Introduction of VSEPR

For the react...

Question

For the reaction $C_{2} H_{4} (g) + 3 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)$ , the difference between enthalpy change and internal energy change is:

- R T

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+ R T

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- 2 R T

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+ 2 R T

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Solution

The correct option is C $- 2 R T$
$C_{2} H_{4} (g) + 3 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)$
$Δ n_{g} = 2 - 3 - 1$
$= - 2$
$Δ H = Δ E + Δ n_{g} R T$

$Δ H - Δ E = Δ n_{g} R T$

$∴ Δ H - Δ E = - 2 R T$
Hence, option C is correct.

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