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Byju's Answer
Standard XII
Physics
Calorimetry
For the react...
Question
For the reaction,
C
3
H
8
(
g
)
+
5
O
2
(
g
)
⟶
3
C
O
2
(
g
)
+
4
H
2
O
(
l
)
at constant temperature,
Δ
H
−
Δ
E
is:
A
+
3
R
T
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B
−
R
T
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C
+
R
T
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D
−
3
R
T
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Solution
The correct option is
D
−
3
R
T
C
3
H
8
(
g
)
+
5
O
2
(
g
)
⟶
3
C
O
2
(
g
)
+
4
H
2
O
(
l
)
Δ
n
is the difference in the number of moles of gaseous products and gaseous reactants.
Δ
n
=
(
3
)
−
(
1
+
5
)
=
−
3
Δ
H
=
Δ
E
+
Δ
n
R
T
Δ
H
−
Δ
E
=
Δ
n
R
T
Δ
H
−
Δ
E
=
−
3
R
T
Hence.option D is correct.
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2
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