For the reaction C(s)+CO2(g)⇔2CO the partialpressures of CO2 and CO are 2.0 and 4.0 atm.respectively at equilibrium. What is the value of Kp for this reaction?
A
0.5
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B
4
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C
8
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D
32
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Solution
The correct option is D 8 The equilibrium reaction is C(s)+CO2(g)⇔2CO. The expression for the equilibrium constant is KP=[CO]2[CO2]. Substitute values in the above expression. KP=[CO]2[CO2]=(4.0)22.0=8.0.