MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Characteristics of Equilibrium Constant

For the react...

Question

For the reaction $C (s) + C O_{2} (g) ⇌ 2 C O (g),$ the partial pressure of $C O_{2}$ and CO is 2.0 and 4.0 atm, resprectively at equilibrium, The $k_{p}$ of the reaction is:

A

8 a t m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

16 a t m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

12 a t m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $8 a t m$
The given reaction is
$C O_{2} \to 2 C O$
we know, for this case
$K_{P} = \frac{P_{C O}^{2}}{P_{C O_{2}}} P_{C O} = 4 a t m$
$P_{C O_{2}} = 2 a t m$
putting the values,
$= \frac{16}{2} \Rightarrow 8 a t m$

Suggest Corrections

thumbs-up

36

Similar questions

Q. For the reaction

C (s) + C O_{2} (g) ⇌ 2 C O (g),

the partial pressure of

C O_{2}

and CO is 2.0 and 4.0 atm, resprectively at equilibrium, The

k_{p}

of the reaction is:

Q. For the reaction,

C (s) + C O_{2} (g) ⇌ 2 C O (g)

, the partial pressure of

C O

C O_{2}

2.0

4.0

atm respectively at equilibrium. The

K_{p}

for the reaction is:

Q. For the reaction,

C (s) + {C O}_{2} (g) ⇌ 2 C O (g)

, the partial pressure of

{C O}_{2}

C O

2.0

4.0

atm, respectively. At equilibrium the

K_{p}

of the reaction is:

Q. For the reaction

C (s) + C O_{2} (g) ⇌ 2 C O (g),

the partial pressure of

C O_{2}

and CO is 2.0 and 4.0 atm, resprectively at equilibrium, The

k_{p}

of the reaction is:

C (s) + C O_{2} (g) ⇋ 2 C O (g)

For the given reaction, the partial pressures of

C O_{2}

and CO are 4.0 and 4.0 respectively at equilibrium, what is the value of

K_{p}

for this reaction?

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Characteristics of Equilibrium Constant

Standard XIII Chemistry

Join BYJU'S Learning Program

CrossIcon