For the reaction, $C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g), K_{p} = p_{C O_{2}}$ .

True

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False

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Solution

The correct option is A True
The equilibrium reaction is $C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)$ .
Thus $K_{p} = \frac{P_{C O_{2}} P_{C a O}}{P_{C a C O_{3}}} = P_{C O_{2}}$ .
Because $P_{C a O} = P_{C a C O_{3}} = 1$ as the concentrations of the solid substances are considered as unity.

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