471
Question
For the reaction CO(g)+12O2(g)→CO2(g), ΔH=−67.37 Kcal at 25o C. The change in entropy in the accompanying process is −20.7 cal deg−1mol−1. The change in free energy at 25o C is
For the reaction CO(g)+12O2(g)→CO2(g), ΔH=−67.37 Kcal at 25o C. The change in entropy in the accompanying process is −20.7 cal deg−1mol−1. The change in free energy at 25o C is
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Solution
The correct option is D −61.2 kcal mol−1
ΔH=−67.3 kcal mol−1
ΔS=−20.7 cal deg−1mol−1
ΔG=ΔH−TΔS
ΔG=−67.3kcal mol−1−298×(−20.7×10−3 kcal mol−1)
=−67.3+6.1686kcal mol−1
ΔG=−61.2 kcal mol−1
ΔH=−67.3 kcal mol−1
ΔS=−20.7 cal deg−1mol−1
ΔG=ΔH−TΔS
ΔG=−67.3kcal mol−1−298×(−20.7×10−3 kcal mol−1)
=−67.3+6.1686kcal mol−1
ΔG=−61.2 kcal mol−1
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