Question

For the reaction $H_{2}O\left(s\right)\leftrightharpoons H_{2}O\left(l\right)$ at 0°C and normal pressure

• A. $△$H > T$△$S
• B. $△$H = T$△$S
• C. $△$H = $△$G
• D. $△$H < T$△$S

Answer 1

The correct option is B

$△$H = T$△$S

Let's look at the reaction.
$H_{2}O\left(s\right)\leftrightharpoons H_{2}O\left(l\right)$ at $0^{\circ }C$
It will be in equilibrium at $0^{\circ }C$
Now, At equilibrium
$△$G = 0
&$△$G = $△$H - T$△$S
$\Rightarrow △$H - T$△$S = 0
$\Rightarrow △H=T△S$