For the reaction $K O_{2} + H_{2} O + C O_{2} ⟶ K H C O_{3} + O_{2}$ , the mechanism of reaction suggests :

acid-base reaction

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disproportionation reaction

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hydrolysis

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redox change

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Solution

The correct options are
A disproportionation reaction
B hydrolysis
C redox change
D acid-base reaction
The mechanism of the reactions suggests the following:
$4 K O_{2} + 2 H_{2} O ⟶ 4 K O H + 3 O_{2}$ [Hydrolysis, disproportionation and redox]
$4 K O H + 4 C O_{2} ⟶ 4 K H C O_{3}$ [Acid-base reaction].

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Similar questions

K O_{2} + H_{2} O + C O_{2} ⟶ K H C O_{3} + O_{2}

K O_{2} + H_{2} O + C O_{2} \to K H C O_{3} + O_{2}

K O_{2} + H_{2} O + C O_{2} \to K H C O_{3} + O_{2}

K O_{2}

C O_{2}

H_{2} O

4 K O_{2} (s) + 2 H_{2} O (l) \to 3 O_{2} (g) + 4 K O H (s)

C O_{2}

K O H_{s w} + C O_{2} (g) \to K H C O_{3} (s)

K O_{2}

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K O_{2}

C O_{2}

H_{2} O

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