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Question

For the reaction : MnO2+4HCl100%−−−→MnCl2+Cl2+2H2O, 17.4 g MnO2 is dissolved in 500 mL of HCl solution containing 7.3 g HCl per litre. (molar mass of Mn=55 g/mol)

A
HCl is the limiting reagent
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B
MnO2 is the limiting reagent
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C
0.05 moles of MnCl2 will form
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D
1120 mL Cl2 gas will be liberated at 0 oC and 1 atm
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Solution

The correct option is D 1120 mL Cl2 gas will be liberated at 0 oC and 1 atm
MnO2+4HCl100%−−MnCl2+Cl2+2H2O

moles of MnO2=17.487=0.2
moles of HCl=7.336.5=0.2

moles of MnO2stoichiometric coefficeint=0.21=0.2

moles of HClstoichiometric coefficeint=0.24=0.05

HCl is a limiting reagent.

4 moles of HCl form 1 mole of Cl2
nCl2 formed from 0.2 mol of HCl=0.05
as molar volume at STP = 22.4 L
VCl2=0.05×22.4=1120 mL
Similarly, moles of MnCl2=14moles of HCl
nMnCl2=0.05

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