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Assigning Oxidation Numbers

For the react...

Question

For the reaction, $N_{2} + 3 H_{2} ⟶ 2 N H_{3}$ . If $E_{1}$ and $E_{2}$ are equivalent masses of $N H_{3}$ and $N_{2}$ respectively, then $E_{1} - E_{2}$ is :

A

1

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B

2

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C

3

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D

4

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Solution

The correct option is A 1
$N_{2} + 3 H_{2} ⟶ 2 N H_{3}$
0 -3
So, eq. wt of $N_{2} = \frac{28}{6} = E_{2}$
Similarly, eq wt of $N H_{3} = \frac{17}{3} = E_{1}$
$E_{1} - E_{2} = 1$

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