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Derivation of Kp and Kc

For the react...

Question

For the reaction $N_{2 (g)} + O_{2 (g)} ⇌ 2 N O_{(} g)$ , the value of $K_{c}$ at $800^{0}$ C is $0.1$ . What is the value of $K_{p}$ at this temperature?

0.5

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0.1

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Solution

The correct option is D $0.1$
$N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)$

$K_{p} = K_{c} (R T)^{Δ n}$
here, $Δ n = 2 - (1 + 1) = 0$
Since $Δ n = 0, K_{p} = K_{c}$
$(R T)^{0} = 1$
$K_{p} = 0.1 \times 1 = 0.1$

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