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Standard XII

Chemistry

Rate of Reaction

For the react...

Question

For the reaction $R \to P,$ the concentration of a reactant changes from $0.03$ M to $0.02$ M in $25$ minutes. Calculate the average rate of reaction both in minutes and seconds.

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Solution

Average rate of reaction = $- \frac{Δ [R]}{Δ t}$
$⟹ - \frac{[R]_{2} - [R]_{1}}{t_{2} - t_{1}}$
$⟹ - \frac{0.02 - 0.03}{25} = 4 \times 10^{- 4} M m i n^{- 1}$
Also, it can be expressed in seconds as:
Average rate of reaction $= \frac{4 \times 10^{- 4}}{60} = 6.67 \times 10^{- 6}$

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For the reaction R→P, the concentration of a reactant changes from 0.03 M to 0.02 M in 25 minutes. Calculate the average rate of reaction both in minutes and seconds.

Average rate of reaction = −Δ[R]Δt ⟹−[R]2−[R]1t2−t1 ⟹−0.02−0.0325=4×10−4M min−1 Also, it can be expressed in seconds as: Average rate of reaction=4×10−460=6.67×10−6

For the reaction $R \to P,$ the concentration of a reactant changes from $0.03$ M to $0.02$ M in $25$ minutes. Calculate the average rate of reaction both in minutes and seconds.

Average rate of reaction = $- \frac{Δ [R]}{Δ t}$
$⟹ - \frac{[R]_{2} - [R]_{1}}{t_{2} - t_{1}}$
$⟹ - \frac{0.02 - 0.03}{25} = 4 \times 10^{- 4} M m i n^{- 1}$
Also, it can be expressed in seconds as:
Average rate of reaction $= \frac{4 \times 10^{- 4}}{60} = 6.67 \times 10^{- 6}$