For the reactions, $P C l_{5} (g) ⇌$ $P C l_{3} (g) + C l_{2} (g), K_{p} a n d K_{c}$ are related as:

K_{p} = K_{c} (R T)

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K_{p} = \frac{K_{c}}{(R T)}

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K_{p} = 2 K_{c} (R T)

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K_{p} = 4 K_{c} (R T)

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Solution

The correct option is D $K_{p} = K_{c} (R T)$
As we know,
$K_{p} = K_{c} (R T)^{Δ n}$
Here, $δ n = 2 - 1 = 1$ so
$K_{p} = K_{c} (R T) .$

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Similar questions

P C I_{5} (g) ⇌ P C I_{3} (g) + C I_{2} (g)

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P C l_{3} (g) + C l_{2} (g) ⇌ P C l_{5} (g), K_{c}

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For $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g) + h e a t$

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